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Engineering Question involving Moment Diagrams?

Alright, I'm trying to study for this building technology II class and were discussing Moment Diagrams. I'm trying to understand it. I know how to do it without uniform loads, but I can seem to understand how they are drawn with uniform loads. I'm reading the textbook and it gives me this example.

R1= 17.8k
R2= 8.8k

4' from R1 is a load of 21k and there is a uniform load of 400 lb/ft. The beam is 14'. Draw the moment diagram.

I understand everything except where they get one number from.

M(x=4)= (17.8k*4) - (.400*4*2)= 68k

Where does the times 2 come from? I don't understand it and the book doesn't explain it. Can you help me figure this out?

In the term (400*4*2), 400*4 = the load at x=4' due to the equally distributed load of 440 lb/ft, and the *2 is the average distance multiplier for the equally distributed load that will then give you the moment.

The moment = force x distance
The force = 400 lb/ft and the distance at which it acts from x = 2 ft.

MIE341 - Engineering Drawing Tips


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